The solubility of gas is 0.58 g/l at a pressure of 104 kpa. what is the solubility if it’s solubility pressure increases to 250 kpa at the same temperature?

Answer : The solubility of gas at pressure 250 kPa is, 1.39 g/L

Explanation:

According top the Henry's Law, the solubility of a gas in a liquid is directly proportional to the pressure of the gas.

or,

where,

= initial solubility of gas = 0.58 g/L

= final solubility of gas = ?

= initial pressure of gas = 104 kPa

= final pressure of gas = 250 kPa

Now put all the given values in the above formula, we get the final solubility of the gas.

Therefore, the solubility of gas at pressure 250 kPa is, 1.39 g/L

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