120.0j of energy are added to a sample of air with unknown mass. the sample increases its temperature from 33.2°c to 45.0°c. what is the mass of the air sample? (c=1.0 j/g°c)

The mass of the air  sample  is calculated using  the below

Q(heat)=M(mass) x C(specific heat capacity) x delta T(change  in temperature)

Q= 120.j
M=?
C= 1.0j/g/c
delta T =45.0-33.2=11.8 c
by making M the subject of the formula

M=Q/C delta T

  = 120 j/ 1.0 j/g/c x11.8 c=10.17 grams

Your answer is a just took the test