Pl
5. the following equations represent part of a radioactive decay series:
1. 92238u -> a + 24he
2. a -> 91234pa + b
3. 91234pa -> c + –10e
4. c -> 90230th + 24he
5. 90230th -> d + 24he
6. d -> 86222rn + e
7. 86222rn -> 84218po + f
8. 84218po -> g + 24he
9. g -> 83214bi + h
10. 83214bi -> i + –10e
11. i -> j + 24he
fill in the table with the correct particle or element, and describe the types of radiation given off in the series.

Due to the emitted particle is an electron, this is a β⁻ decay. In this decay a neutron is converted into a proton by emitting an electron. Since parent atom is ₉₁²³⁴Pa, Daughter atom should have 91 + 1 = 92 as the atomic number. Hence, the daughter atom should be U (Uranium) but mass number is same as parent atom is 234.

4. answer is ₉₂²³⁴U

The parent atom undergoes an alpha decay. Hence, the mass number is reduced by 4 while atomic number is reduced by 2 in the product. The product is ₉₀²³⁰Th, The atomic number should be 90 + 2 = 92 in Parent atom which belongs to U (Uranium). But mass number should be 230 + 4 = 234.

5. D should be ₈₈²²⁶Ra.

This is an alpha decay. Hence, atomic number of daughter atom is less than atomic number of parent atom by 2 and the mass number of daughter atom is less than the mass number of parent atom by 4. Since parent atom has 90 as atomic number, daughter atom should have 90 - 2 = 88 as the atomic number. Hence, the daughter atom should be Ra (Radium). But the mass number should be 230 - 4 = 226.

6. E is ₂⁴He.

D is ₈₈²²⁶Ra. Produced daughter atom is given as ₈₆²²²Rn. The mass number of daughter atom is reduced by 4 while reducing the atomic number by 2 than parent atom. Hence, this is an alpha decay. Hence, the emitted particle should be ₂⁴He.

7. F is ₂⁴He.

Parent atom is ₈₆²²²Rn. Produced daughter atom is given as ₈₄²¹⁸Po. The mass number of daughter atom is reduced by 4 while reducing the atomic number by 2 than parent atom. Hence, this is an alpha decay. Hence, the emitted particle should be ₂⁴He.

8. G should be ₈₂²¹⁴Pb.

This is an alpha decay. Hence, atomic number of daughter atom is less than atomic number of parent atom by 2 and the mass number of daughter atom is less than the mass number of parent atom by 4. Since parent atom has 84 as the atomic number, daughter atom should have 84 - 2 = 82 as the atomic number which belongs to Pb (Lead). But the mass number should be 218 - 4 = 214.

9. H is ₋₁⁰β (₋₁⁰e)

answer: the figure is attached herewith.

step-by-step explanation:   we are given to sketch a unit circle and label the terminal points corresponding to

in the attached figure, we have drawn a unit circle, with centre at o(0,0) and radius 1 unit. we have labelled the points a, b, c, d and e corresponding to the angles below

∠aox = 60°,

∠box = 120°,

∠cox = 180°,

∠dox = 240°,

∠eox = 300°.

and the coordinates are a(0.5,1), b(-0.5,1), c(-1,0), d(-0.5,-1) and e(0.5,-1).

thus, the answer is complete.

convalent bond :

is a chemical bond formed by the sharing of electron between 2 atoms.

it is the direct chemical bond between 2 atoms.

in bond formation atoms are involved here.

electrovalent bond:

is a chemical bond defined as electroststic attraction between 2 atoms.

it is the electrostatic attraction between 2 atoms.

in bond formation, ions are involved here.

hope it

and ur welcm

: )