What is the volume occupied by 11.0 grams of a gas at stp if the molecular mass of the gas is 44.0?

We can use the ideal gas law equation to find the volume occupied by the gas
PV = nRTwhere 
P - standard pressure - 101 325 Pa
V - volume
n - number of moles  - 11.0 g / 44 g/mol = 0.25 mol
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - standard temperature - 273 K
substituting the values in the equation 
101 325 Pa x V = 0.25 mol x  8.314 Jmol⁻¹K⁻¹ x 273 K
V = 5.60 L
volume of the gas is 5.60 L

The answer is a) carbon-12