How much grams of mg(oh)2 is formed if 103g of h2o reacted? (round answer to the nearest tenths) mg2si+ > 2mg(oh)2 + sih4 (improvised arrow above not an inequality sign)

             117 g of Mg(OH)₂

Solution:
The equation is as follow,

                             Mg₂Si  +  4 H₂O     →     2 Mg(OH)₂  +  SiH₄

According to equation,

            72 g (4 moles) H₂O produces  =  116.64 g (2 mole) Mg(OH)₂
So,
                  103 g of H₂O will produce  =  X g of Mg(OH)₂

Solving for X,
                      X  =  (116.64 g × 103 g) ÷ 72 g

                      X  =  116.86 g ≈ 117 g of Mg(OH)₂

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