Suppose that 26.89 ml of vinegar solution requires 33.23 ml of the 0.09892 m sodium hydroxide solution to reach the endpoint. calculate the molar concentration of the vinegar solution.

Number of millimoles of NaOH consumed in present titration =33.23 X 0.09892
                                                                                                 = 3.287

Thus, number of millimoles of vinegar present in sample = 3.287

Now, Molarity of vinegar solution = 
                                                     = 
                                                     = 0.1222 mol/dm3

Molar concentration of vinegar present in sample solution is 0.1222 M 

Hey how did you manage to type such a big lab report