How much 0.85 m hcl solution can be made by diluting 250 ml of 10 m hcl?

Answer is:  2940 mL of the HCL solution.

c₁(HCl) = 10.0 M.

V₂(AgNO₃) = ?.
c₂(AgNO₃) = 0.85 M.
V₁(AgNO₃) = 250 mL ÷ 1000 mL/L = 0.25 L.

c₁ - original concentration of the solution, before it gets diluted.
c₂ - final concentration of the solution, after dilution.
V₁ - volume to be diluted.
V₂ - final volume after dilution.
c₁ · V₁ = c₂ · V₂.
V₂(HCl) = c₁ · V₁ ÷ c₂.

V₂(HCl) = 10 M · 0.25 L ÷ 0.85 M.

V₂(HCl) = 2.94 L · 1000 mL = 2940 mL.

the answer is 1260

you spend 7 hours in school for 1 school day with 5 school days in 1 school week with 36 school weeks in a school year.

7*5*36= 1260 it's all about multiplying