When sucrose, c12h22o11, is dissolved in h2o in the presence of an acid catalyst it reacts according to the equation c12h22o11 + h2o → 2 c6h12o6 with a rate law of rate = k[c12h22o11]. if 3.00 g of sucrose decreases to 2.70 g in 2.50 hours in the presence of a certain concentration of an acid cata?

Reaction involved in present system is :   c12h22o11 + h2o → 2 c6h12o6the reaction system is obeying following rate law:   rate = k[c12h22o11]thus, it is a first order reaction.now, for 1st order reactionrate constant (k) =  given: initial conc. = 3.0 g, final conc. = 2.7 g, t = 2.5 h∴rate constant (k) =  ∴ k = 0.04215 h-1now, for 1st order reaction, half life = 0.693/k = 0.693/0.04215 = 16.4 hthus correct answer is option b

It's not the same dearthe first one is in grams per mole while the other is not

Idon't see the pic?