If a sample of oxygen gas occupies a volume of 2.15 at a pressure of 0.572 atm and a temperature of 25 c what volume would this sample occupy at stp

            1.126 L

Solution:

Let's assume the gas is behaving ideally, then initial and final states of given gas are given as,

                                      P₁ V₁ / T₁  =  P₂ V₂ / T₂    (1)
Data Given;

                  P₁  =  0.572 atm

                  V₁  =  2.15 L

                  T₁  =  25 °C + 273  =  298 K

                  P₁  =  1.00 atm

                  V₂  =  ?

                  T₂  =  0 °C + 273  =  273 K

Solving equation 1 for V₂,

                 V₂  =  P₁ V₁ T₂ / T₁ P₂

Putting Values,

                 V₂  =  (0.572 atm × 2.15 L × 273 K) ÷ (298 K × 1 atm)

                 V₂  =  1.126 L