A random sample of residents in city J were surveyed about whether they supported raising taxes to increase bus service for the city. From the results, a 95 percent confidence interval was constructed to estimate the proportion of people in the city who support the increase. The interval was (0.46,0.52).

C. More than 40 percent of the residents support the increase

Explanation:

Options includes "A. More than 90 percent of the residents support the increase. B. Fewer than 10 percent of the residents support the increase. C. More than 40 percent of the residents support the increase. D. More than 60 percent of the residents support the increase. E. Fewer than 25 percent of the residents support the increase."

As 95% confidence interval is (0.46,0.52) therefore actual proportion lies in between 0.46 to 0.52. Therefore the actual proportion of people who support the increase is surely greater than 0.40 Therefore more than 40% residents support the increase. Therefore the option (c) is correct.

answer; /// the above statement is (true);

the first one $24,630