In a shuffleboard game, the puck slides on a horizontal floor before coming to complete stop. If the coefficient of kinetic friction between the puck and floor is 0.5 and the initial speed of the puck is 14.8m/s what distance did the puck travel (in meters before coming to a stop? Use kinematics and forces for in your solution (i. e. not energy).

22.33 m

Explanation:

We are given;

Coefficient of kinetic friction between the puck and floor; μ = 0.5

initial speed of the puck; u = 14.8m/s

From Newton's equation of motion, we know that;

v² = u² + 2as

But since it decelerate to rest, the acceleration will be negative.

Thus;

v² = u² - 2as

Final velocity is zero, thus;

0 = u² - 2as

Thus, a = u²/2s

Where s is the distance covered before coming to rest.

Now, we know that formula for the frictional force is;

F = μmg

F/m = μg

We also know that F/m = a

Thus, a = μg

Thus:

u²/2s = μg

s = u²/(2μg)

s = 14.8²/(2 × 0.5 × 9.81)

s = 22.33 m

if it is for a job, then you should learn everything you can about the job, like what does it involve, what qualification is required and how you are the right person for that job. dress appropriately for the interview. get plenty of rest the night before. good luck!

answer decisions made by individual households and firms;