Business, 21.05.2020 21:59 AdoNice

A professor of statistics claimed that the average amount of money a typical college

student spends per day during social distancing at home is over $70. Based upon

previous research, the population standard deviation is estimated to be $17.32. The

professor surveys 35 students and finds that the mean spending is $67.57. Is there

evidence that the average amount spent by students is less than $70? State hypotheses,

calculated value, critical value at a = 0.1

the professor wants to know wether the sample mean 67.57 is high enough.

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Answers

We fail to reject the Null hypotheses that the average amount of money a typical college student spends per day is less than $70.

Explanation:

A professor of statistics claimed that the average amount of money a typical college student spends per day during social distancing at home is over $70.

Based upon previous research, the population standard deviation is estimated to be $17.32.

The professor surveys 35 students and finds that the mean spending is $67.57.

Is there evidence that the average amount spent by students is less than $70?

For the given problem the Null hypotheses is that the average amount of money a typical college student spends per day is less than $70.

$H_0= \mu$

For the given problem the Alternate hypotheses is that the average amount of money a typical college student spends per day is over $70.

$H_1= \mu 70$

The test statistic is given by

$z = \frac{\bar{X}-\mu}{\frac{\sigma}{\sqrt{n} } }$

Where X_bar is the sample mean spending that is $67.57, μ is the average population spending that is $70, σ is the standard deviation that is 17.32 and n is the sample size that is 35.

$z = \frac{67.57-70}{\frac{17.32}{\sqrt{35} } }\\\\z = \frac{-2.43}{ 2.927}\\\\z = -0.83$

The p-value corresponding to the z-score of -0.83 at significance level 0.10 is found to be

p-value = 0.2036

Since 0.2036 > 0.10

We fail to reject the Null hypotheses that the average amount of money a typical college student spends per day is less than $70.

Answer from: Quest

the effect is that geography has alot to do with how level the ground is and how structurally safe it is. it can also show like cracks in the ground and if mountains are safe to be by. hope this

Answer from: Quest

start by isolating the variable on one side by adding 43w^2 to both sides. the equation will read:

25w^2+5=0

*subtract 5 from both sides*

25w^2=-5

*divide both sides by 25*

w^2=-1/5

*take the square root of both sides*

w=√(-1/5)

the square root of -1 is i. the square root of 5 remains √5

the answer is i/√5.

hope this

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