Each plate consists of 6 characters: 3 numbers followed by 3 letters. You are allowed to have repetitions of letters and numbers. Find the probability that a randomly chosen license plate has.

Hi your question is incomplete but the two possible scenarios would be the probability of a randomly chosen license plate having repeated numbers or repeated letters since the repetitions of letters and numbers are allowed

Explanation:

If each plate consists of 6 characters which includes 3 numbers and 3 letters

The total number of plates that can be formed using this combination ( including repetition of number and letters ) will be

possible occurrence of letters = 26 ( a - z )

possible occurrence of numbers = 10 ( 0 - 9)

number of letters given = 3

number of digits given = 3

Hence total possible occurrence of letters will be ( possible occurrence of letters³(number of letters given) )

= 26*26*26 = 17576

Total possible occurrence of numbers will be ( possible occurrence of numbers³(number of digits given))

= 10*10*10 = 1000

The total number of plates that can be formed using the combination of 3 numbers followed by 3 letters will be

= 17576 * 1000 = 17576000

probability of repeated numbers = 1000 / 17576000 = 0.0056%

probability of repeated letters = 17576 / 17576000 = 0.1 %

107x106 is the answer