The retained earnings account has a credit balance of $37,000 before closing entries are made. total revenues for the period are $55,200, total expenses are $39,800, and dividends are $9,000. what is the correct closing entry for the revenue accounts? a) debit revenue accounts $55,200; credit income summary $55,200. b) debit revenue accounts $37,000; credit retained earnings $37,000 c) debit revenue accounts $55,200; credit retained earnings $37,000. d) debit income summary $55,200; credit revenue accounts $55,200. debit income summary $37,000; credit retained earnings $37,000

Ateam of engineers has decided to design a new shoe for people suffering from a painful foot condition. what should the engineers do during the planning stage of their project? a. look at the trial's results to see how the design can be improved. b. build a variety of shoe models. c. have patients wear the new shoe in an experimental trial to see if symptoms improve. d. estimate how much potential consumers would be willing to pay for this new shoe.

Thirty years ago daniel bought a plot of land for $50,000 when the cpi was 50. now the cpi is 180 and he sold the land for $180,000. what issue might inflation cause for daniel?

Add the mips assembly language instructions (after main: ) to complete the following (in this order). do not skip steps. use other registers as needed. actions: 1. initialize the register $s0 to 35 2. prompt the user to enter a number, read the number and then put it into register $s1 3. prompt the user to enter a number, read the number and then put it into register $s2 4. store the value in $s1 into the memory at address 0x10010000. 5. store the value in $s2 into the memory at address 0x10010004. 6. calculate the value of $s0 - $s1 $s2 and store the result in the memory at address 0x10010008. 7. print the following output each on its own line. you will need to determine the location of each of the strings from the beginning of the memory segment a. your name b. the value in address 0x10010000 c. the value in address 0x10010004 d. the value in address 0x10010008 8. exchange or swap the values in $s1 and $s2 9. set the value in $s0 to -$s0