There are two teams of students: team a with 3 sophomores, 8 juniors and 13 seniors; and team b with 5 sophomores, 7 juniors and 6 seniors. suppose we pick one student from each team at random. find the probability that both students are of the same type (that is, both sophomores, or both juniors, etc).

sopomores= 0.0397

juniors= 0.1481

seniors= 0.2063

Explanation:

Giving the following information:

There are two teams of students:

Team A with 3 sophomores, 8 juniors, and 13 seniors. Total of 24 students.

Team B with 5 sophomores, 7 juniors, and 6 seniors. Total of 18 students.

First, we need to calculate the probability of selecting any student on each team:

Team A:

sophomores=3/21= 0.1428

juniros= 8/21= 0.3809

senors= 13/21= 0.619

Team B:

sopomores= 5/18= 0.2778

juniors= 7/18= 0.3889

seniors= 6/18= 0.3333

Now, we can calculate the probability of selecting the same type of students:

sopomores= 0.1428*0.2778= 0.0397

juniors= 0.3809*0.3889= 0.1481

seniors= 0.619*0.3333= 0.2063

answer may be d i think

x=3

step-by-step explanation:

this is really simple i saw that there was only one term (5x) and thought if that was 15 what would i have to multiply everything else to get it there? well if 5x became 15 then x would have to be 3 so plug the 3 in the x for the other equations and you get 15 for the other ones. so there you go. : )