Awallet contains five $10 bills, three $5 bills, and seven $1 bills (nothing larger). if the bills are selected one by one in random order, what is the probability that at least two bills must be selected to obtain a first $10 bill? (round your answer to three decimal places.)

The probability that at least two bills must be selected to obtain a first $10 bill is 0.67.

Explanation:

Let X be the number of trials to get first $10 bill

p ⇒ is the probability of getting $10 bill, that is,

=

In this question, X follows the geometric distribution,

The geometric distribution gives the likelihood that the first event of progress requires k independent trials, each with progress likelihood p. In the event that the likelihood of success on every trial is p, at that point the likelihood that the kth trials (out of k preliminaries) is the first success is

{\displaystyle \Pr(X=k)=(1-p)^{k-1}p} {\displaystyle \Pr(X=k)=(1-p)^{k-1}p}

for k = 1, 2, 3, ....

P( X ≥ 2 )  = ?

P( X ≥ 2 )   = 1 - P( x < 2 )

P( x < 2 ) = P( x = 1 ) = ×

So,

P( X ≥ 2 )   = 1 - 0.33

= 0.67

the investment was $14,174.196

explanation:

a lump sum means that the father of the example made one deposit and leave it be.

we need to know the value of a capital that generated at 4.05% per year during 28 years the sum of $48,613.24

now clearing the formula to solve for capital we got:

and we reach the answer investment = $14,174.20

lbc corporation makes and sells a product called product wz. each unit of product wz requires 4.1 hours of direct labor at the rate of $20.00 per direct labor-hour. management would like you to prepare a direct labor budget for june. the company plans to sell 28,000 units of product wz in june. the finished goods inventories o