In chickens, a flat single comb is a recessive trait, while the short, thick rose comb is dominant. in a particular population of chickens, 45 are homozygous for the dominant trait, 30 are heterozygous dominant, and 25 have the recessive trait. which expression is the correct way to calculate the frequency of the recessive allele?

The correct answer would be 0.5

The same can be explained with the help of Hardy-Weinberg equation

p² + q² + 2pq = 1

p + q = 1 Where,

Total number of individuals = 45 + 30+ 25 = 100

So, the frequency of recessive trait = 25/100 =0.25.

Thus, the value of q² = 0.25

So, q would be equal to square root of 0.25 which comes out to be 0.5

i think it is dna, i'm not totally sure but i think it might be.

step 1: initiation

initiation is the beginning of transcription. it occurs when the enzyme rna polymerase binds to a region of a gene called the promoter. this signals the dna to unwind so the enzyme can ‘‘read’’ the bases in one of the dna strands. the enzyme is now ready to make a strand of mrna with a complementary sequence of bases.

step 2: elongation

elongation is the addition of nucleotides to the mrna strand. rna polymerase reads the unwound dna strand and builds the mrna molecule, using complementary base pairs. there is a brief time during this process when the newly formed rna is bound to the unwound dna. during this process, an adenine (a) in the dna binds to an uracil (u) in the rna.

step 3: termination

termination is the ending of transcription, and occurs when rna polymerase crosses a stop (termination) sequence in the gene. the mrna strand is complete, and it detaches from dna.