Biology, 31.07.2019 02:30 keke6361

What is the association between tropomyosin and troponin molecules in resting striated muscle fibers?

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The correct answer is that "troponin holds the tropomyosin in place on the actin".

In excitation-contraction coupling, tropomyosin prevents the interaction between actin and myosin in resting muscles. In the event of excitation, there is release of calcium from the sarcoplasmic reticulum wherein the troponin will bind this calcium and will release tropomyosin and expose myosin enabling it to attach to actin and therefore facilitating muscle contraction.

Answer from: estherklein15ov3vx9

Answering the question, the association between tropomyosin and troponin molecules in resting striated muscle fibers is such that troponin holds the tropomyosin in place on the actin.

The actin protein is the main part of thin filament but there are two other components which are tropomyosin and troponin.

Further Explanation

However, the actin protein consists of binding sites that can hold myosin, that is, the actin has binding sites that where myosin can be attached. When the muscles are at rest, the Tropomyocin blocks the interactions between actin and myosin which prevent the cross-bridging formation as well as a contraction in muscles.

However, the troponin is made up of three globular subunits. One of the subunits connects with tropomyosin while the other two binds with actin and ca 2+ ions respectively.

Also, to allow a muscle contraction, there must a change in the way the tropomyosin reacts, the change of formation is necessary to enable cross bridge-formation.

Muscle contractions also required the presence of calcium and it must also be at a very low concentration within the sarcoplasm.

The presence of calcium would make it possible for calcium ions to joins with tropomyosin and muscle contraction can then take place.

LEARN MORE:

The molecule that is the independent force-generator in muscle fibers is Smooth muscle cells lack which protein(s)?

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fiberscalicum

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the median of the data is 4.5.

Answer from: Quest

Could you elaborate?

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