In a dihybrid cross with genotypes jjqq and jjqq, what is the probability of getting an offspring with genotype jjqq?  

1/4

Explanation:

A dihybrid cross is a cross between two individuals in which two different traits are analyzed.

In the problem, the genes are J/j and Q/q.

To analyze the genotypes of the offspring, a Punnett Square is needed. See the image attached. If you count them, the genotype JjQq appears 2 out of 8 times, so the probability of getting that genotype in the offspring is 2/8 = 1/4.

answer; i believe its echoic memory,it is believed to last three to four seconds; good luck

hey, i believe your answer would be d. sugar ribose and the base uracil. i believe this is the answer, because rna consists of sugar ribose, adenine, guanine, cytosine, and uracil.

your first option is incorrect, because that's dna. where it consists of sugar deoxyribose, adenine, guanine, cytosine and thymine.

your second option is also incorrect, this is because sugar deoxyribose is in dna, and uracil is in rna. these two do not make sense together.

your third option being incorrect, because sugar ribose is in rna, but not the base of thymine. rna consists of uracil, not thymine.

lastly your fourth option being correct! this answer is correct, because both sugar ribose, and the base uracil are in rna! ~

answer is d. sugar ribose and the base uracil.