An anaerobic metabolic pathway that results in the production of two net ATPs per glucose plus two pyruvic acid molecules is glycolysis True False

True.

Explanation:

Glycolysis is a process that occurs in the cell cytoplasm, in which a 6-carbon glucose molecule is cleaved into two 3-carbon pyruvate molecules. Two molecules of ATP (Adenosine triphosphate, a molecule that acts as a source of energy to perform biological processes.) and two molecules of NADH are also obtained. It is a metabolic pathway responsible for oxidizing glucose in order to obtain energy for the cell. It consists of a series of consecutive enzymatic reactions, and when pyruvate is obtained, it continues to be used in other metabolic pathways in order to continue delivering energy to the organism. Glycolysis takes place both in the absence and presence of oxygen, so it is defined as an anaerobic process. Therefore, the final destination of the products obtained in glycolysis will depend on the conditions of the environment in which it is found, which will determine the metabolic pathway to be followed (i.e., whether oxygen is available or not). In the absence of oxygen, glucose will not be completely oxidized to carbon dioxide and water, generating fermentative products (lactic acid in animals and ethanol in yeast) producing only two net ATP molecules. In the presence of oxygen, the pyruvate obtained during glycolysis enters the Krebs cycle (to produce energy in usable form as ATP or GTP) and then undergoes oxidative phosphorylation (the process by which ATP is formed as a result of electron transfer from NADH or FADH2 to oxygen via a series of electron transporters) producing a net gain of between 36-38 ATP.

the answer for apex is "1 and 6"