If a radioisotope has a half-life of 17.5 days, how much of that radioisotope will remain from a 100 gram sample after 70 days?

Okay! Had to do some research, but now I'm here.

Explanation:

So, to do this, half-life is a sort of time period where half of the starting material naturally decays into a stable element, such as uranium.

Meaning, after 17.5 days, 50 grams of that radioisotope will be left.

After 35 days (2 half-lives), 25 grams of that radioisotope will be left.

See where I'm getting at?

After 52.5 days, 12.5 grams of the radioisotope will be left.

(It's easier to create a graph, but I'm using a simple progression method to solve this.)

As such, after 70 days, 6.25  grams of that radioisotope will be left.

See? Pretty easy. Just keep adding the amount of the half-life, and divide the starting material by two!

Hope this helps!

You can calculate by given steps.

Explanation:

A Use Equation 14.28 to calculate the half-life of the reaction. B Multiply the initial concentration by 1/2 to the power corresponding to the number of half-lives to obtain the remaining concentrations after those half-lives. C Subtract the remaining concentration from the initial concentration.

lysosomes contain a variety of enzymes, enabling the cell to break down various biomolecules it engulfs, including peptides, nucleic acids, carbohydrates, and lipids (lysosomal lipase). the enzymes responsible for this hydrolysis require an acidic environment for optimal activity. hope i !

answer; i believe the correct answer is (sporophyte);