Given the hyperbola (y2/16) – (x2/9) = 1, find the equations for its asymptotes.
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ANSWER:

Since your hyperbola has the "y" term listed first, it opens "up and down.'

It's also centered at (0,0)

So the form is: y²/b² - x^²/a² = 1

In your case,

b² = 16

so, b = √(16) = 4.

And a² = 9

so, a = √(9) = 3.

So, the equations for the asymptotes are y = +(b/a)x and y = -(b/a)x

So we have, in your case,

y = +(4/3)x and y = - (4/3)x.

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explanation:

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