Determine the results from a cross of a mother who is heterozygous for tongue rolling with a father who is homozygous recessive

In order to determine the results from a father who is homozygous recessive for the tongue rolling trait, T, and a mother who is heterozygous for the trait, a Punett square can be used to determine both the resulting genotype (allele combination) and phenotype (observable characteristics). The results are 50% Tt and 50% tt. Thus, the cross would result to 1:1 ratio of tongue rolling to non-tongue rolling offsprings. 

A, if i am wrong correct me

The virus is considered to be are living item since they have hereditary material dnas or rnas. they can imitate and change. they respond to boosts, for example, radiation, chemicals, and warmth. they have antigenic properties. they are proficient to duplicate with a same hereditary constituent.