Starchy grain is dominant over sugary corn. if, in a cross between these types, 58 of the progeny are sugary, how many of the progeny should be starchy

Let us solve first the phenotype of this problem.

Starchy grain = AA (dominant)

Sugary Corn = aa (recessive)

AA x aa = ;

     A    A

a  Aa   Aa

a  Aa   Aa

The result of the cross is that the progeny will become heterozygous.

If there is 58 progeny sugary, there will also be 58 starchy. It is 50%.