In a cell containing 10 chromosomes, meiosis results in the formation of daughter cells containing chromosomes.

5 chromosomes. Meiosis results in 4 haploid cells, meaning they have "n" pairs of chromosomes. The diploid cell that the 10 chromosomes originated in has "2n" pairs. This leaves us with a simple equation to solve the problem, 2n=10, so n must equal 5 chromosomes.

"In a cell containing 10 chromosomes, meiosis results in the formation of daughter cells containing 5 chromosomes each".

Explanation:

Meiosis is a process in which from one cell containing a diploid number of chromosomes (2n), four daughter cells with a haploid chromosome number (n) are produced. Each daughter cell has half of the chromosomes of the original one.

There are two phases in meiosis: the first one in which it occurs a chromosome´s reduction division, and the second one in which it occurs a new division but this one is not a reductive one.

The first phase, Meiosis I: Chromosomes condensate and became visible. It occurs crossing-over between homologous chromosomes in the equatorial plane, that makes the daughter cells to be genetically different from the original one. After crossing-over, homologous chromosomes get separated again. Then it occurs cytokinesis and chromosomes became lax again. The second phase, Meiosis II: Chromosomes condensate again, they join the spindle apparatus and migrate to the equatorial plane. Centromeres divide and each chromatid goes forward each pole. Once in the poles, chromosomes became lax again and it occurs cytokinesis.

In the exposed example, there are ten original chromosomes which suffer meiosis and result in the formation of four cells containing five chromosomes each.

The 2n number is 10 in the original cell,

After the first meiotic phase where it occurs the reduction, haploid chromosomes number are left in each cell.

The haploid number, n, is 5 in each daughter cell.

The answer is observations and interpreting.

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