This pedigree chart tracks the inheritance of a recessive trait that is not sex-linked. based on the information in the chart, which of the following statements is true about individuals 3 and 4?
at least one is heterozygous for the trait.
they are both homozygous dominant for the trait.
they are both heterozygous for the trait.
at least one is homozygous for the trait.

They are both heterozygous for the trait.

They both express the dominant trait, but one of the offspring is recessive. The only option for this is that both are heterozygous and have two genes: recessive and dominant.

You can see this when you draw a Punnett square.

Subject 3 will be Dd where D is the dominant trait, and d is the recessive trait. Subject 4 will be Dd.

Now cross them, and you'll found 25% chances of having a recessive offspring.

You can't have only one of them heterozygous because, when you draw the Punnett square, you'll have 50% dominant and 50% dominant heterozygous.

The same happened with only one homozygous.

And, if they were both homozygous dominant you only have one trail, no two, and again you can't have a recessive offspring.

d. in sexual reproduction, offspring have more chromosomes than

either parent.

asexual reproduction results in offspring which are genetically the same as the parent organism (not counting a rare mutation). sexual reproduction produces a random mixture of the genetics derived from both parents

explanation:

it is a learned trait

explanation: