Can someone help me with this question, please!!

Genotypic- 1:1

Phenotypic- 1:1

Explanation:

For this problem, I will use the letter A to represent the alleles. The first parent's genotype would be Aa, and the second parent would be aa. Then, using a punnet square to cross the two parents the outcome is Aa, Aa, aa, aa. This means there is a 50% of a mixed individual and a 50% of a purebred recessive. Both phenotypes also have a 50% chance of being expressed. Since the percentages are equal both ratios are 1:1.

i'm gonna put a couple so you can chose from

explanation:

if you know the fur color of the offspring mice, you can use the ratios to identify the genotypes of the parents.

if either parent mouse passes a dominant allele, the offspring will have black fur.

if the parental mice has two different fur color (i.e white and black) , the color of the offspring's fur would be either black, white, or the combination of both (grey)

hope this : )

i think its the first one