If the average length of a double helix in human chromosome is 3.9 cm, approximately how many base pairs are present in such chromosome?

The average length of a double helix in human chromosome whose length is 3.9 cm has approximately 114.7 million base pairs

Explanation:

Lenght of DNA = number of base pairs * distance between consecutive base pairs

The distance between two consecutive base pairs bonded by hydrogen bonds is 0.34 nm.

If the average length of a double helix DNA molecule in human chromosome is 3.9 cm, the average number of base can then be calculated using the formula below:

Average number of base pairs = length of DNA ÷ distance between consecutive base pairs

Average number of base pairs = 3.9 cm/ 0.34 nm = 0.039 m/ 0.00000000034 m

Average number of base pairs = 114705882.4

Therefore, the average length of a double helix in human chromosome whose length is 3.9 cm has approximately 114.7 million base pairs