Estimate the electric field in the membrane wall of a living cell. Assume the wall is 14 nmnm thick and has a potential of 0.11 VV across it.

The electric field in the membrane wall of a living cell is 7.857 x 10⁶ V/m.

Explanation:

Given;

thickness of the membrane wall, d = 14 nm = 14 x 10⁻⁹ m

potential of the membrane wall, V = 0.11 V

The electric field in the membrane wall of a living cell is calculated as;

Therefore, the electric field in the membrane wall of a living cell is 7.857 x 10⁶ V/m.

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