In a dihybrid cross, if the genotypes of one the parents is BbTT, what genes would you put on the outside of the Punnett square? Answers:

BT, Bt, BT, Bt

BT, BT, BT, BT

BB, bb, TT, tt

BT, BT, bT, bT

BT, BT, bT, bT

Explanation:

According to Mendel's law of independent assortment, the alleles of a gene will separate into gametes independently of one another i.e. one allele of a gene does not hinder the separation of another. The separation occurs via meiosis in such a way that only one allele of a gene is present in each GAMETE.

These gametes are what forms the crossing basis in a punnet square. According to this question involving a dihybrid cross, the genotype of one of the parents is BbTT. The allelic combination of the gametes will be: BT, BT, bT, bT. These gametes will be put on the outside of the Punnett square.

BT,BT,bT,bT

Explanation:

It's 50/50.

if you add everything up correctly you should get 69 i got this because 50 plus 19 is it

c.           is the correct answer