A farmer has found several strawberries in his field that are sweeter and larger in size than the rest of the field. How Could this farmer reproduce strawberry plants similar to those he has found in this field?

The correct answer is 3.5 grams

Explanation:

In the given question, there is a need to use the equation R = h² × S. Here, R is the response to selection, it is the difference between the mean of the initiating population and the mean of the progeny of the selected parents. In the given question R = 5g - 2g = 3g.  

S is the selection differential, it is the difference between the mean of the initiating population and the mean of the selected parents. In the given case, S = 6g - 2g = 4g

Substituting the values of R and S in the given equation, we get:  

3g = h² (4g)

h² = 0.75

If the selected plants' average weight is 4 grams, then S would be 2 grams, and R = 0.75 × 2 = 1.5g

The predicted average weight of strawberries from the progeny plants would be 2g + 1.5g = 3.5 g.  

answer: accepted answer: aquatic animals use the oxygen dissolved in water to carry out respiration. since the amount of dissolved oxygen in water is low as compared to the amount of oxygen in the air, therefore the rate of breathing in aquatic animals is much faster than it is in terrestrial animals.

explanation:

during the process of dna replication, brdu can replace thymidine and incorporate into the newly synthesized dna, cell proliferation thus can be reflected in the extent of brdu incorporation.