The ability to taste the chemical PTC is determined by a single gene in humans with the ability to taste given by the dominant allele T and the inability to taste by the recessive allele t. Suppose two heterozygous tasters (Tt) have a large family. What is the likelihood that their first child will be a taster

75%

Explanation:

This question involves a single gene coding for the ability to taste the chemical PTC. The allele coding for the ability to taste (T) is dominant over the allele coding for the inability to taste (t). This means that an heterozygous individual will have the ability to taste PTC.

According to this question, if two heterozygous tasters (Tt) cross to have a large family i.e. Tt × Tt, the following gametes will be produced by each parent;

Tt = T and t

Using these gametes in a punnet square (see attached image), the following proportion of offsprings will be produced:

TT, Tt, Tt - Tasters (3/4 or 75%)

tt - Non-taster (1/4 or 25%)

Note that based on the question asked, there is a 75% probability that their first child will be a taster because there is equal segregation of alleles into gametes.

Mitochondria is the cell organelle that produced the energy that is needed in the body system in form of atp, that is why it is called the power house of the cell. energy is needed by the living organisms to carry out the activities which sustain life.  if the mitochondria is destroyed atp will not be produced. if the mitochondria is destroyed, energy production will stop and the affected living organism will not have the energy to carry out the necessary life processes; this will lead to the death of the organism.

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