Multiply. (3x2 – 2x)(2x2 + 3x - 1)
O A. 6x4 + 5x3 - 9x2 - 2x
O B. 6x4 + 5x3 – 3x2 + 2x
O C. 6x4 + 5x3 - 9x2 + 2x
O D. 5x4 + 2x3 - 8x2 + 2x

C

(3·x^2 - 2·x)·(2·x^2 + 3·x - 1)

= 3·x^2·2·x^2 + 3·x^2·3·x - 3·x^2·1 - 2·x·2·x^2 - 2·x·3·x + 2·x·1

= 6·x^4 + 9·x^3 - 3·x^2 - 4·x^3 - 6·x^2 + 2·x

= 6·x^4 + 5·x^3 - 9·x^2 + 2·x

Explanation:

hope this helps UwU

if it is correct and you make me brainliest

multiplying and dividing the two decimals and the eqations by the same number of the overalls

easy

explanation: