In cocker spaniels, black coat color ( B) is dominant over red ( b), and solid color ( S) is dominant over spotted ( s). In the F 2 generation of a cross between BB ss with bb SS, what fraction of the offspring would be expected to be black and spotted

The correct answer is -3/16

Explanation:

The cross between BBss and bbSS In cocker spaniels will form gametes that are - Bs and bS. As it is given that  black coat color ( B) is dominant over red ( b), and solid color ( S) is dominant over spotted ( s) then f1 gen would be :

      Bs      Bs

bS BbSs  BbSs

bS  BbSs  BbSs

Now F2 generation;

       BS        Bs        bS        bs

BS   BBSS   BBSs   BbSS   BbSs

Bs   BBSs    BBss   BbSs   Bbss

bS   BbSS   BbSs   bbSS    bbSs

bs   BbSs   Bbss   bbSs     bbss

Here black-spotted that is possible only in two cases, BBss or Bbss, are 3/16

the sunflower because each experiment got the same results

hope this !

-payshence

idk what the options are but

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