A chemist reacts 97.13 g of Sn(NO2)4 and 75.44 g of Pt3N4 as shown below. Sn(NO2)4 + Pt3N4 --> Sn3N4 + Pt(NO2)4

Part a) Calculate the maxium mass of Sn3N4 that can be produced.
Part b) Identify the limiting reactant.
Part c) Calculate the maximum mass of Pt(NO2)4 that can be produced from this reaction.
Part d) When complete, the reaction actually produced 106.53 g of Pt(NO2)4. Calculate the percent yield.

Select all answer choices that apply to questions a-d.
Note: calculated values are rounded to 2 decimal places.
Group of answer choices

Pt3N4

44.08

87.58

133.8

48.49

117.18

121.64

Sn(NO2)4