E. coli strain B is doubly infected with two rII mutants of phage T4. 0.2 ml of a 108 dilution of the progeny is plated on E. coli B and 0.1 ml of a 104 dilution of the progeny is plated on E. coli K. 16 plaques appeared on strain B, 400 on strain K. Calculate the recombination frequency between these two mutations.

Given:

The formula:

→

By putting the values in the above formula, we get

→        

→        

→        

Thus the solution above is the right approach.

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To Find :

The recombination frequency between these two mutations.

Solution :

Formula of calculating recombination frequency is :

Putting all given values in above equation, we get :

Therefore, the recombination frequency between these two mutations is 0.01 or 1 %.

1) gene flow

- it is described as the transfer of genes from one population to another population so that frequency of gene is increased.

-a zebra migrates to join a different herd of zebras.

2) natural selection

- a mechanism of evolutionary change in which individuals with advantageous traits survive and reproduce whereas the others ( those that can not adapt) eliminate from the population.

-competition for sunlight leads to taller trees.

3) mutation

- permanent change in the nucleotide sequence of dna ( genetic material) that could have harmful or useful consequences.

-the dna of a snake changes to make its venom stronger.

4) genetic drift - it is a random phenomenon ( that occurs by chance such as fire) that results in change in the gene frequency in a small population.    

-a grassfire randomly sweeps through a population of buffalo and kills most of the animals.

explanation:

i think it’s c but i might be wrong. if i am let me know! have a good rest of your day as well!