What is the percentage composition of each element in dinitrogen monoxide, N2O? A) 58.32% N; 41.68% O
B) 60.55% N; 39.45% O
C) 63.64% N; 36.36% O
D) 62.66% N; 37.34% O

Answer

C) 63.64% N; 36.36% O

Expalnation:

first we find the mollar mass of the compound

μ=AO+2AO(A is the atomic mass)

μ=16+28=44g/mole

the mass of O in the molecule is 16 the mass of N is 28

16=x/100*44=>x=36,36%O2

28=y/100*44=>y=63,64%N

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