In guinea pigs the allele for black fur (B) is dominant over the allele for brown fur (b), and the allele for short fur (F) is dominant over the allele for long fur (f). What percentage of the offspring from a BBFF x bbff cross would be expected to be heterozygous for both traits?

100%

Explanation:

This question involves two genes in guinea pigs; one coding for fur color and the other for fur length. The alleles of black fur (B) and short fur (F) is dominant over the alleles for brown fur (b) and long fur (f).

In a cross between two offsprings with genotypes: BBFF x bbff, the following gametes will be produced by each parent:

BBFF - BF, BF, BF, and BF

bbff - bf, bf, bf, bf

Using these gametes in a punnet square (see attached image), one will notice that all of the offsprings will have the genotype: BbFf i.e all or 100% of the offsprings are heterozygous for both of the genes or traits.

nucleus

would be most reasonable answer tbh

step 1: nitrogen fixation- conversion of atmospheric no₂ into forms useful to plants by lightning, bacteria, and cyanobacteria.

step 2: nitrification-process of converting ammonia to nitrite or nitrate.

step 3: assimilation-plant roots absorb new form of nitrogen.

step 4: ammonification-conversion of organic nitrogen to ammonia by bacteria involved in decomposition.

step 5: denitrification-bacteria turns the decomposed matter back into n₂o, which is released into atmosphere; repeat cycle.