A population has 1000 individuals. A PCR analysis of the genotypes of a gene associated with Lactase persistence are: LL = 450 Ll = 250 ll = 300. What are the allelic frequencies of the L and l alleles?

L allele: 0.575 (or 57.5%)

l allele: 0.425 (or 42.5 %)

Explanation:

Homo-zygous individuals have two copies of the same allele (i.e., either L alelle or l allele), while heterozygous individuals carry both alleles at a time (i.e., one L allele and one l allele). In consequence:

- Frequency of the L allele: [(450 x 2) + 250] / 2000 = 0.575

- Frequency of the l allele: [(300 x 2) + 250] / 2000 = 0.425

primary succession begins with a bare rock and ends with a forest secondary succession begins after a natural disaster where there is a temporary setback after a forest fire or local destruction, but the surrounding area can fill in

hey, i believe your answer would be d. sugar ribose and the base uracil. i believe this is the answer, because rna consists of sugar ribose, adenine, guanine, cytosine, and uracil.

your first option is incorrect, because that's dna. where it consists of sugar deoxyribose, adenine, guanine, cytosine and thymine.

your second option is also incorrect, this is because sugar deoxyribose is in dna, and uracil is in rna. these two do not make sense together.

your third option being incorrect, because sugar ribose is in rna, but not the base of thymine. rna consists of uracil, not thymine.

lastly your fourth option being correct! this answer is correct, because both sugar ribose, and the base uracil are in rna! ~

answer is d. sugar ribose and the base uracil.