Learning Task 2. Find the equation of the line . Write in slope intercept form and in standard form
1. m = -5, b= 1
3. (-2, 0) and (0,5)
2. (1, -2), (3, 3)
4. a = 2, b = -7
5.m=2,(3,-1)

(1)  m = -5, b= 1

put b=1 (given)

=> y = -x/a + 1

-1/a is representing slope here which is given as -5

-1/a = -5 => a = 1/5

slope intercept form

y = mx +b

y = -5x + 1

standard form

5x +y = 1

(2). (1, -2), (3, 3)

m = 5/2

slope intercept form

y - 3 = 5/2*( x -3)

y = 5x/2  -9/2

standard form

5x -2y = 9

(3). (-2, 0) and (0,5)

  m = 5/2

slope intercept form

y - 0 = 5/2 ( x+2)

y = 5x/2 + 5

standard form

5x -2y = -10

(4). a = 2, b = -7

slope intercept form  

y = 7x/2 -7

standard form

7x -2y =14

(5). m=2,(3,-1)

  slope intercept form  

y +1 = 2(x -3)

y = 2x -7

standard form

2x -y = 7

hey, i believe your answer would be d. sugar ribose and the base uracil. i believe this is the answer, because rna consists of sugar ribose, adenine, guanine, cytosine, and uracil.

your first option is incorrect, because that's dna. where it consists of sugar deoxyribose, adenine, guanine, cytosine and thymine.

your second option is also incorrect, this is because sugar deoxyribose is in dna, and uracil is in rna. these two do not make sense together.

your third option being incorrect, because sugar ribose is in rna, but not the base of thymine. rna consists of uracil, not thymine.

lastly your fourth option being correct! this answer is correct, because both sugar ribose, and the base uracil are in rna! ~

answer is d. sugar ribose and the base uracil.

b. read the phase at the intersection of any given temperature and pressure.