Please help I need some to calculate this for me.

Pro Tip 1: To calculate the % of cells at rest (in interphase), divide the number of cells in interphase by the total # of cells in the slide (cells in telophase may look like they are almost 2 cells, but you can still count them as 1).
# of cells in interphase ÷ total cells = % of cells at rest

Pro Tip 2: To calculate the % of cells dividing (or mitotic index), add up the cells in prophase, metaphase, anaphase and telophase. Divide that number by the total # of cells in the slide.
# of cells in PMAT ÷ total cells = % of cells dividing (or mitotic index)

INTERPHASEPROPHASEMETAPHASEANAPHASETELOPHASE% of Cells at Rest (interphase)

% of Cells Dividing (Mitotic Index)

Normal Lung

13 cells2 cells2 cells2 cells1 cell65%35%

Cancerous Lung  6 cells5 cells3 cells  3 cells3 cells30%70%

Normal Stomach  10 cells  3 cells  3 cells  3 cells  1 cell50%50%

Cancerous Stomach  5 cells5 cells  4 cells  4 cells  2 cells  25%75%

Normal Ovary  9 cells  5 cells  3 cells  1 cell2 cells45%55%

Cancerous Ovary3 cells  6 cells5 cells3 cells3 cells  15%85%

Explanation:

The answers are also down below in the chart if that helps you better make sense of them.

There are 20 cells in each column, to find the ones at rest we simply take the first number in the column and devide it by the number of cells (in this case 20) once we find the percent of cells at rest, we subtract from 100 to see the cells deviding!

Hope this helps another student along the way! :)

Good luck with your studies and have a fantastic winter break!

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explanation:

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an individual’s sex (i.e., whether they are a male or female) is determined by the sex chromosomes. most people have two sex chromosomes, one that is inherited from their mother and one that is inherited from their father. typically, females have two x chromosomes (xx) and males have one x chromosome and one y chromosome (xy). conditions caused by changes (“mutations”) in genes located on the x chromosome are considered x-linked.

x-linked recessive inheritance

most x-linked conditions are recessive. this means that in a person with two x chromosomes (most females), both copies of a gene (i.e., one on each x chromosome) must have a change or mutation whereas in a person with one x chromosome (most males), only one copy of a gene must have a mutation. a female with a mutation in one copy of a gene on the x chromosome is said to be a “carrier” for an x-linked condition. a male with a mutation in a gene on the x chromosome is typically affected with the condition. because females have two copies of the x chromosome and males have only one x chromosome, x-linked recessive diseases are more common among males than females. however, x-linked recessive diseases can occur in both males and females.

for x-linked recessive disorders, an unaffected carrier mother who has a mutation in a gene on the x chromosome can transmit either the x chromosome with this mutation or a “normal” x chromosome to her children. if the father is unaffected, none of her daughters will be affected and all of her daughters will be unaffected—since they will inherit at least one normal x chromosome from their father. however, each daughter will have a 50% chance of being an unaffected carrier like her mother and a 50% chance of both x chromosomes being normal.