If two heterozyotes for dwarfism have children what proportion of their kids would you expect to be of typical size and not exhibit dwarfism?

3/4 or 75%

Explanation:

This question involves a gene coding for height in humans. The allele for normal height (D) is dominant to the allele for dwarfism (d).

If two heterozygotes for dwarfism are crossed i.e. Dd × Dd, the following gamete will be produced by each heterozygote parent:

Dd - D and d

Using these gametes in a punnet square (see attached image), the genotypes of the expected offsprings will be as follows- DD (1) : Dd (2) : dd (1)

(1) DD - typical normal size

(2) Dd - heterozygous normal size

(1) dd - dwarf

The offsprings expected to be of typical size and not exhibit dwarfism are offsprings DD and Dd, which represent 3/4 of the offsprings. Hence, the proportion is 3/4 or 3/4 × 100 = 75%.

not the best question format lol but what i think might as scale color is controlled by a single gene with two alleles, the green allele and the yellow allele. when moths that are homozygous for green scales are mated with moths that are homozygous for yellow scales, 100% of the offspring have green scales.