What energy yield (in molecules of ATPATP per molecule of monosaccharide) would you predict for the bacterial catabolism of raffinose, a trisaccharide

The correct answer is 2.67 ATP per molecule.

Explanation:

With the help of sucrose, it comes to known that the dissociation of a sugar-sugar bond generates one phosphorylated monosaccharide. Therefore, raffinose, which is a trisaccharide exhibits bonds of two sugar-sugar molecules. Post dissociation, they will generate one regular monosaccharide and two phosphorylated monosaccharides.  

There will be the generation of net ATPs by each phosphorylated monosaccharide as they are already phosphorylated. While the regular monosaccharide, which is first needed to get phosphorylated will only produce two ATPs. Thus, a total of 8 ATPs will be produced by one molecule of raffinose. After dividing by three monosaccharides, the molecule will produce 8/3 = 2.67 ATPs per monosaccharide.  

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