A farmer plants Bt cotton that is genetically modified to produce its own insecticide. Of the cotton bollworms feeding on these Bt plants, only 8% survive unless they have at least one copy of the dominant resistance allele R that confers resistance to the Bt insecticide. When the farmer first plants Bt cotton, the frequency of the R allele in the cotton bollworm population is 0.4. What will the frequency of the resistance allele be after one generation of cotton bollworms fed on Bt cotton

Hardy-Weinberg principle states that are used to calculate the genetic variation of a population at equilibrium.

The frequency of the resistance allele in the cotton bollworm is 0.6.

Hardy-Weinberg equation can be given as:

P² + 2PQ + Q² = 1

where,

P = dominant allele (R)

Q = recessive allele (r)

Frequency of R allele = 0.4

From the equation:

P + Q = 1

or,

Q = P - 1

Genetic frequency of the R allele  = P² = 0.4 x 0.4 = 0.16

Substituting the values:

Q = 1 - 0.4

Q = 0.6

Q² = 0.36

Thus, the frequency of the resistance allele will be 0.6.

To know more about the Hardy-Weinberg principle, refer to the following link:

link

0.6

Explanation:

According to hardy-weinberg principle,

P2+2pq+q2=1

P+q=1

q=1-p

Given that Allele R frequency is 0.4

and p represent the dominant allele

P=0.4

P2=0.4^2 = 0.16 for genotypic frequency

Since p+q=1

q=1-p

where q stands for recessive allele r frequency and q2 stands for genotypic frequency for allele r

q= 1-0.4= 0.6

q2=0.6 ^2

q2=0.36

correct answer is option a.

tropopause, stratopause and mesopause have all in common aspect that is point of maximum temperature in its layer of the atmosphere. all layers of atmosphere observe abrupt change in temperature. tropopause is the boundary between troposphere and stratosphere. stratopause is the boundary between stratosphere and mesosphere. mesopause is the boundary between mesosphere and thermosphere. these all boundaries are ranges between altitude of 0 to 80 km.

the correct answer should be false

{apex}