Two-point testcrosses revealed the following map results: The distance between pm and ss is 9 map units. The distance between pm and bb is 14 map units. Required:
a. What are the two possible maps for this region?
b. What cross would resolve the two possible maps?

Explanation:

Based on this information we can say that the only two possible maps for this region would be the following

a. ) pm--9--ss--5--bb or bb--14--pm--9--ss

b.) Using these two maps as guides we can also determine that the cross used for each individual map would be a two-point test cross between ss and bb. With these results you can determine that if the distance is 5 mu then the first map (pm--9--ss--5--bb) is ultimately correct, otherwise, if the distance is 23 mu , the second map (bb--14--pm--9--ss) is correct

i don't know. the other person does though.

the answer is; comparing the frequency of collisions with and without the device

this makes the anti-collision system an independent variable and the collisions a dependent variable. if there are fewer collisions with an anti-collision system that without, then it can be stated that the system is a success. essentially, collisions under an anti-collision system are compared with the frequency of collisions by cars with the human drivers.