Which statement correctly compares metaphase I and metaphase II? A) in metaphase 2 twice as many chromosomes line up along the middle of the cell as I’m metaphase 1.

B) in metaphase 1 twice as many chromosomes line up along the middle of the cell as in metaphase 2

C) in metaphase 2 twice as many chromosomes are pulled to opposite ends of the cell as in metaphase 1

D) In metaphase 1 twice as many chromosomes are pulled to opposite ends of the cell as in metaphase 2

B.

I hope this helps :)

Explanation:

Metaphase I -The first metaphase of meisosis I encompasses the alignment of paired chromosomes along the center (metaphase plate) of a cell, ensuring that two complete copies of chromosomes are present in the resulting two daughter cells of meiosis I. Metaphase I follows prophase I and precedes anaphase I.

Metaphase II-The second stage in meiosis II after prophase II, and highlights the alignment of chromosomes along a single plane in the center of the cell.

answer-

the statement that f(x) = |x+a| + b has exactly one x-intercept is sometimes correct.

solution-

it solely depends on b, whether the function will have one or two or zero x intercept.

this plot of the given function, f(x) = |x+a| + b will be the basic absolute value graph i.e v shape, with vertex translated to (-a, b), instead of origin.

1-   if b is zero, the graph will have exactly one x-intercept, at x= -a

2- if b is positive, the whole graph will be above the x-axis, hence it will have no x-intercepts.

3- if b is negative, the graph will be below the x-axis, hence it will have two x-intercepts.

∴ the statement is sometimes true.