Topic Test Active
TIME REMAINING
12
13
14
15
16
17
18
01:40:13
Students in Mr. Klein's chemistry class are conducting an experiment to calculate the specific heat of a copper sample. Mr.
Klein requires each lab team to repeat the experiment until their percent error is 2% or less. Percent error is calculated
using observed values (those students calculate from their lab results) and the true value (the accepted value based on
reference). The formula for percent error is:
(observed - true) x 100
true
If the accepted value for the specific heat of copper is 0.385 J/gºC, which of the following lab
teams have an unresolved problem on their hands?
team 1: calculates 0.390 J/gºC
b team 2: calculates 0.395 J/gºC
both teams
d neither team
C
Please select the best answer from the choices provided

b. Team 2: calculates 0.935 J/g degrees celsius.

Explanation:

i think that the best answer would be c.

tell me if im wrong : )

it has to be understood that the sea water contains a huge amount of sodium and chlorine ions and if they enter the cell of the atlantic cod fish, the cell will shrivel and the fish will die. to avoid such a condition, the fish uses active transport for the purpose of removing the ions against the gradient.

explanation:

the atlantic cod is not a maritime osmoconformer. its native application of salts is less than that of the seawater it lives in. it is continually falling water from the gills to the ocean via osmosis.

countering that, the fish is going to be swallowing seawater. but since its internal collection of salts is lower than seawater, the fish will want to go free of excess salt, and since that's going upon a gradient, then active transport, requiring energy, must be used to pump out the salt. much marine fish use the organs to filter out the salt and these fish discharge very straight urine.