if the ratio of the ages of kisii and esinam is 3:5 and that of Esinam and Larry is 3:5 and the sum of the ages of all three is 147 years what is the age difference between the oldest and the youngest

The age difference between the oldest and the youngest is 48.

Explanation:

Given the following data;

The ratio of the ages of Kisii (K) and Esinam (E) is 3:5.

The ratio of the ages of Esinam (E) and Larry (L) is 3:5.

The sum of the ages of all three is 147.

Since the age of Esinam is common in both ratios, we find the lowest common multiple (LCM);

LCM of 3,5 = 15.

Hence, the ratio of the three ages is now;

K:E:L = 9:15:25

Let their ages be denoted by x;

The sum of all three ages is;

9x + 15x + 25x = 147

49x = 147

x = 147/49

x = 3.

To find the age difference between the oldest and the youngest;

The oldest is Esinam = 25x

The youngest is Kisii = 9x

Therefore, 25x - 9x = 16x

Substituting the value of x, we have;

x = 3; 16x = 16(3) = 48.

The age difference between the oldest and the youngest is 48.

no moderator inbox me? ?