What is the correct stoichiometry of products of the citric acid cycle (assume 1 mol of glucose is being oxidized):-2 mol pyruvate, 2 mol ATP (equivalent), 2 mol OAA, 6 mol NADH, 2 mol FADH2, 4 mol CO2.-2 mol pyruvate, 2 mol ATP (equivalent), 0 mol OAA, 6 mol NADH, 2 mol FADH2, 4 mol CO2.-2 mol acetyl-CoA, 2 mol ATP (equivalent), 2 mol OAA, 6 mol NADH, 2 mol FADH2, 4 mol CO2.-2 mol acetyl-CoA, 2 mol ATP (equivalent), 0 mol OAA, 6 mol NADH, 2 mol FADH2, 4 mol CO2.-2 mol acetyl-CoA, 2 mol ATP (equivalent), 2 mol OAA, 6 mol NADH, 2 mol FADH2, 6 mol CO2.-2 mol acetyl-CoA, 2 mol ATP (equivalent), 0 mol OAA, 6 mol NADH, 2 mol FADH2, 6 mol CO2.

The stoichiometry products of the citric acid cycle assuming one molecule of glucose is oxidized are as follows:

2 mol acetyl CoA, 2 mol ATP equivalent, 2 mol OAA, 6 mol NADH, 2 mol FADH2, 4 mol CO2

Explanation:

Citric acid cycle is a pathway designed to burn away carboxylic acids as two molecules. The citric acid cycle accepts 2 carbon molecules and oxidizes it to water and carbon dioxide. After glycolysis, pyruvate is converted to acetyl CoA which enters the citric acid cycle.

Considering the oxidation of sugar, one molecule of glucose generates 4 NADH while being converted to acetyl CoA. One molecule of glucose undergoes two round of citric acid cycle . 2 mol of CO2 are released in each turn of the cycle.

Each turn of the cycle yields 3 NADH molecules and one FADH2 molecule. One ATP molecule is formed in each cycle.

Through the two rounds of citric acid cycle, one molcule of glucose generates 6 NADH, 2 FADH2, 2 ATP and 4 CO2 in total.

it would be the percentage of food eaten by the flock

i remember doing this lab