In a certain population of rabbits, the allele first brown fur is dominant over the allele for white fur. If 60 out of 100 rabbits have white fur, what is the allele frequency for the recessive allele?
The Hardy-Weinberg equation is:
[homozygous dominant]2 + 2[heterozygous] + [homozygous recessive]2= 1

Well, Your answer will be is 0.01 Because, The Hardy-Weinburg equation is p + q = 1, or p^2 + 2pq + q^2 = 1, where p is dominant and q is recessive. If 10 out of 100 rabbits have white fur, 10% of the rabbits have white fur. Therefore, 90% of the rabbits have brown fur, which can be substituted into the first equation to become 0.9 + 0.1 = 1. Now that we know what p and q equal, we can solve the rest of the equation.

0.9^2 = 0.81

0.9 * 0.1 * 2 = 0.18

0.1^2 = 0.01

So, The best answer will be is 0.01 Good Luck!

From ~Itsbrazts~.

prophase: we can observe the chromosomes to coil up and condense. they become visible. nuclear membrane and envelope disintigrate.s

metaphase: chromosomes align at the center, the metaphase plate. spindle fibers attach to centromeres of the sister chromatids. they meet at kinetochores.

anaphase: sister chromatids are pulled towards each opposing centromere, set on different poles.

telophase: chromosomes are now clustered up only on either sides of the cell. nuclear membranes reform, and a new cell wall forms along the cell plate. this will lead to cytokinesis, the process that divides the cell membrane and forms the cell wall.

when you breathe in, or inhale, your diaphragm contracts (tightens) and moves downward. this increases the space in your chest cavity, into which your lungs expand. the intercostal muscles between your ribs also enlarge the chest cavity. they contract to pull your rib cage both upward and outward when you inhale.